Optimal. Leaf size=108 \[ -\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {128}{75} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {338}{225} \sqrt {\frac {2}{5}} \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )+\frac {98}{9} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right ) \]
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Rubi [A]
time = 0.03, antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.269, Rules used = {100, 159, 163,
56, 222, 95, 210} \begin {gather*} \frac {338}{225} \sqrt {\frac {2}{5}} \text {ArcSin}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )+\frac {98}{9} \sqrt {7} \text {ArcTan}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {5 x+3}}-\frac {128}{75} \sqrt {5 x+3} \sqrt {1-2 x} \end {gather*}
Antiderivative was successfully verified.
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Rule 56
Rule 95
Rule 100
Rule 159
Rule 163
Rule 210
Rule 222
Rubi steps
\begin {align*} \int \frac {(1-2 x)^{5/2}}{(2+3 x) (3+5 x)^{3/2}} \, dx &=-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {2}{5} \int \frac {\sqrt {1-2 x} \left (\frac {167}{2}+64 x\right )}{(2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {128}{75} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {2}{75} \int \frac {\frac {2633}{2}-169 x}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {128}{75} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {338}{225} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx-\frac {343}{9} \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {128}{75} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {686}{9} \text {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )+\frac {676 \text {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{225 \sqrt {5}}\\ &=-\frac {22 (1-2 x)^{3/2}}{5 \sqrt {3+5 x}}-\frac {128}{75} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {338}{225} \sqrt {\frac {2}{5}} \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )+\frac {98}{9} \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )\\ \end {align*}
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Mathematica [A]
time = 0.18, size = 104, normalized size = 0.96 \begin {gather*} \frac {30 \sqrt {1-2 x} (-357+10 x)-338 \sqrt {30+50 x} \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )+12250 \sqrt {7} \sqrt {3+5 x} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{1125 \sqrt {3+5 x}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.11, size = 139, normalized size = 1.29
method | result | size |
default | \(\frac {\left (845 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) x -30625 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x +507 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-18375 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+300 x \sqrt {-10 x^{2}-x +3}-10710 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {1-2 x}}{1125 \sqrt {-10 x^{2}-x +3}\, \sqrt {3+5 x}}\) | \(139\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.51, size = 86, normalized size = 0.80 \begin {gather*} -\frac {8 \, x^{2}}{15 \, \sqrt {-10 \, x^{2} - x + 3}} + \frac {169}{1125} \, \sqrt {10} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) - \frac {49}{9} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) + \frac {1448 \, x}{75 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {238}{25 \, \sqrt {-10 \, x^{2} - x + 3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.60, size = 127, normalized size = 1.18 \begin {gather*} -\frac {169 \, \sqrt {5} \sqrt {2} {\left (5 \, x + 3\right )} \arctan \left (\frac {\sqrt {5} \sqrt {2} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 6125 \, \sqrt {7} {\left (5 \, x + 3\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 30 \, {\left (10 \, x - 357\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{1125 \, {\left (5 \, x + 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (1 - 2 x\right )^{\frac {5}{2}}}{\left (3 x + 2\right ) \left (5 x + 3\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 219 vs.
\(2 (76) = 152\).
time = 0.51, size = 219, normalized size = 2.03 \begin {gather*} -\frac {49}{90} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} + \frac {169}{1125} \, \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{4 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} + \frac {4}{375} \, \sqrt {5} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - \frac {121}{250} \, \sqrt {10} {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (1-2\,x\right )}^{5/2}}{\left (3\,x+2\right )\,{\left (5\,x+3\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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